2y^2-2y=-10

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Solution for 2y^2-2y=-10 equation: 



2y^2-2y=-10

We move all terms to the left:

2y^2-2y-(-10)=0

We add all the numbers together, and all the variables

2y^2-2y+10=0

a = 2; b = -2; c = +10;
Δ = b2-4ac
Δ = -22-4·2·10
Δ = -76
Delta is less than zero, so there is no solution for the equation

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